Java Throws

Java throws

Created By: chatGPT

Java provides a mechanism for handling exceptions through the use of the throw and throws keywords. The throw statement is used to explicitly throw an exception, while the throws keyword indicates that a method can throw exceptions, allowing the caller to handle them appropriately.

public void myMethod() throws IOException {
    if (someCondition) {
        throw new IOException("This is an IOException! ");
    }
}

Here, the method myMethod declares that it can throw an IOException. If someCondition is true, it will throw a new IOException with a specified message. The calling method must either handle this exception using a try-catch block or declare it using throws.

public static void main(String[] args) {
    try {
        myMethod();
    } catch (IOException e) {
        System.out.println("Caught an exception: " + e.getMessage());
    }
}

By using throw inside a method, you can control the flow of your application and manage error conditions effectively. It’s crucial to always provide clear and descriptive messages when throwing exceptions, which helps with debugging.

public void validateAge(int age) {
    if (age < 18) {
        throw new IllegalArgumentException("Age must be at least 18.");
    }
}

In the example above, the validateAge method checks if the provided age is less than 18. If so, it throws an IllegalArgumentException with a message. This raises awareness to the caller about the invalid input, ensuring data correctness.

public void processInput(String input) throws ParseException {
    if (input == null) {
        throw new ParseException("Input cannot be null", 0);
    }
    // Processing Logic
}